F(x)=2x^2-48x-87

Solution for F(x)=2x^2-48x-87 equation:

(F)=2F^2-48F-87

We move all terms to the left:

(F)-(2F^2-48F-87)=0

We get rid of parentheses

-2F^2+F+48F+87=0

We add all the numbers together, and all the variables

-2F^2+49F+87=0

a = -2; b = 49; c = +87;
Δ = b2-4ac
Δ = 492-4·(-2)·87
Δ = 3097
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{3097}}{2*-2}=\frac{-49-\sqrt{3097}}{-4}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{3097}}{2*-2}=\frac{-49+\sqrt{3097}}{-4}
$